42=5(2c+9)-3(c+8)

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Solution for 42=5(2c+9)-3(c+8) equation: 



42=5(2c+9)-3(c+8)

We move all terms to the left:

42-(5(2c+9)-3(c+8))=0



We calculate terms in parentheses: -(5(2c+9)-3(c+8)), so:

5(2c+9)-3(c+8)

We multiply parentheses

10c-3c+45-24

We add all the numbers together, and all the variables

7c+21

Back to the equation:

-(7c+21)



We get rid of parentheses

-7c-21+42=0

We add all the numbers together, and all the variables

-7c+21=0

We move all terms containing c to the left, all other terms to the right

-7c=-21

c=-21/-7

c=+3

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