6(x-4)+3x=2x+3(x-5)

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Solution for 6(x-4)+3x=2x+3(x-5) equation: 



6(x-4)+3x=2x+3(x-5)

We move all terms to the left:

6(x-4)+3x-(2x+3(x-5))=0

We add all the numbers together, and all the variables

3x+6(x-4)-(2x+3(x-5))=0

We multiply parentheses

3x+6x-(2x+3(x-5))-24=0



We calculate terms in parentheses: -(2x+3(x-5)), so:

2x+3(x-5)

We multiply parentheses

2x+3x-15

We add all the numbers together, and all the variables

5x-15

Back to the equation:

-(5x-15)



We add all the numbers together, and all the variables

9x-(5x-15)-24=0

We get rid of parentheses

9x-5x+15-24=0

We add all the numbers together, and all the variables

4x-9=0

We move all terms containing x to the left, all other terms to the right

4x=9

x=9/4

x=2+1/4

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