2y-3y-2=5+4(3-y)

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Solution for 2y-3y-2=5+4(3-y) equation: 



2y-3y-2=5+4(3-y)

We move all terms to the left:

2y-3y-2-(5+4(3-y))=0

We add all the numbers together, and all the variables

2y-3y-(5+4(-1y+3))-2=0

We add all the numbers together, and all the variables

-1y-(5+4(-1y+3))-2=0



We calculate terms in parentheses: -(5+4(-1y+3)), so:

5+4(-1y+3)

determiningTheFunctionDomain
4(-1y+3)+5

We multiply parentheses

-4y+12+5

We add all the numbers together, and all the variables

-4y+17

Back to the equation:

-(-4y+17)



We get rid of parentheses

-1y+4y-17-2=0

We add all the numbers together, and all the variables

3y-19=0

We move all terms containing y to the left, all other terms to the right

3y=19

y=19/3

y=6+1/3

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