6(x-3)=4(x-2)-2x

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Solution for 6(x-3)=4(x-2)-2x equation: 



6(x-3)=4(x-2)-2x

We move all terms to the left:

6(x-3)-(4(x-2)-2x)=0

We multiply parentheses

6x-(4(x-2)-2x)-18=0



We calculate terms in parentheses: -(4(x-2)-2x), so:

4(x-2)-2x

We add all the numbers together, and all the variables

-2x+4(x-2)

We multiply parentheses

-2x+4x-8

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

6x-2x+8-18=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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