7(-4+4b)+3=3(-2+3b)

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Solution for 7(-4+4b)+3=3(-2+3b) equation: 



7(-4+4b)+3=3(-2+3b)

We move all terms to the left:

7(-4+4b)+3-(3(-2+3b))=0

We add all the numbers together, and all the variables

7(4b-4)-(3(3b-2))+3=0

We multiply parentheses

28b-(3(3b-2))-28+3=0



We calculate terms in parentheses: -(3(3b-2)), so:

3(3b-2)

We multiply parentheses

9b-6

Back to the equation:

-(9b-6)



We add all the numbers together, and all the variables

28b-(9b-6)-25=0

We get rid of parentheses

28b-9b+6-25=0

We add all the numbers together, and all the variables

19b-19=0

We move all terms containing b to the left, all other terms to the right

19b=19

b=19/19

b=1

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