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6(x-3)=2(2x+5)
We move all terms to the left:
6(x-3)-(2(2x+5))=0
We multiply parentheses
6x-(2(2x+5))-18=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
6x-4x-10-18=0
We add all the numbers together, and all the variables
2x-28=0
We move all terms containing x to the left, all other terms to the right
2x=28
x=28/2
x=14
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