6(x-3)=12-(3-x)+3

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Solution for 6(x-3)=12-(3-x)+3 equation: 



6(x-3)=12-(3-x)+3

We move all terms to the left:

6(x-3)-(12-(3-x)+3)=0

We add all the numbers together, and all the variables

6(x-3)-(12-(-1x+3)+3)=0

We multiply parentheses

6x-(12-(-1x+3)+3)-18=0



We calculate terms in parentheses: -(12-(-1x+3)+3), so:

12-(-1x+3)+3

determiningTheFunctionDomain
-(-1x+3)+12+3

We add all the numbers together, and all the variables

-(-1x+3)+15

We get rid of parentheses

1x-3+15

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

6x-x-12-18=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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