6(x-3)-7=2(2x+3)

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Solution for 6(x-3)-7=2(2x+3) equation: 



6(x-3)-7=2(2x+3)

We move all terms to the left:

6(x-3)-7-(2(2x+3))=0

We multiply parentheses

6x-(2(2x+3))-18-7=0



We calculate terms in parentheses: -(2(2x+3)), so:

2(2x+3)

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

6x-(4x+6)-25=0

We get rid of parentheses

6x-4x-6-25=0

We add all the numbers together, and all the variables

2x-31=0

We move all terms containing x to the left, all other terms to the right

2x=31

x=31/2

x=15+1/2

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