6(x-20)=2(x+4)

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Solution for 6(x-20)=2(x+4) equation: 



6(x-20)=2(x+4)

We move all terms to the left:

6(x-20)-(2(x+4))=0

We multiply parentheses

6x-(2(x+4))-120=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

6x-2x-8-120=0

We add all the numbers together, and all the variables

4x-128=0

We move all terms containing x to the left, all other terms to the right

4x=128

x=128/4

x=32

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