5/26p+7=1/5p

Solution for 5/26p+7=1/5p equation:

5/26p+7=1/5p

We move all terms to the left:

5/26p+7-(1/5p)=0


Domain of the equation: 26p!=0

p!=0/26

p!=0

p∈R



Domain of the equation: 5p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

5/26p-(+1/5p)+7=0

We get rid of parentheses

5/26p-1/5p+7=0

We calculate fractions


25p/130p^2+(-26p)/130p^2+7=0

We multiply all the terms by the denominator


25p+(-26p)+7*130p^2=0

Wy multiply elements

910p^2+25p+(-26p)=0

We get rid of parentheses

910p^2+25p-26p=0

We add all the numbers together, and all the variables

910p^2-1p=0

a = 910; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·910·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*910}=\frac{0}{1820}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*910}=\frac{2}{1820}
=1/910
$