6(x-2)=10(2x+3)

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Solution for 6(x-2)=10(2x+3) equation: 



6(x-2)=10(2x+3)

We move all terms to the left:

6(x-2)-(10(2x+3))=0

We multiply parentheses

6x-(10(2x+3))-12=0



We calculate terms in parentheses: -(10(2x+3)), so:

10(2x+3)

We multiply parentheses

20x+30

Back to the equation:

-(20x+30)



We get rid of parentheses

6x-20x-30-12=0

We add all the numbers together, and all the variables

-14x-42=0

We move all terms containing x to the left, all other terms to the right

-14x=42

x=42/-14

x=-3

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