3(x-2)/2=2(2x+3)/5

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Solution for 3(x-2)/2=2(2x+3)/5 equation: 



3(x-2)/2=2(2x+3)/5

We move all terms to the left:

3(x-2)/2-(2(2x+3)/5)=0

We calculate fractions


3x/()+(-(2(2x+3)*2)/()=0



We calculate terms in parentheses: +(-(2(2x+3)*2)/(), so:

-(2(2x+3)*2)/(

We multiply all the terms by the denominator


-(2(2x+3)*2)



We calculate terms in parentheses: -(2(2x+3)*2), so:

2(2x+3)*2

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12

Back to the equation:

+(-8x-12)



We get rid of parentheses

3x/()-8x-12=0

We multiply all the terms by the denominator


3x-8x*()-12*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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