6(x-2)/2=3(x+4)/7

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Solution for 6(x-2)/2=3(x+4)/7 equation: 



6(x-2)/2=3(x+4)/7

We move all terms to the left:

6(x-2)/2-(3(x+4)/7)=0

We calculate fractions


6x/()+(-(3(x+4)*2)/()=0



We calculate terms in parentheses: +(-(3(x+4)*2)/(), so:

-(3(x+4)*2)/(

We multiply all the terms by the denominator


-(3(x+4)*2)



We calculate terms in parentheses: -(3(x+4)*2), so:

3(x+4)*2

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

-6x-24

Back to the equation:

+(-6x-24)



We get rid of parentheses

6x/()-6x-24=0

We multiply all the terms by the denominator


6x-6x*()-24*()=0

We add all the numbers together, and all the variables

6x-6x*()=0

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