(7(4-z))/6=-z

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Solution for (7(4-z))/6=-z equation: 



(7(4-z))/6=-z

We move all terms to the left:

(7(4-z))/6-(-z)=0

We add all the numbers together, and all the variables

(7(-1z+4))/6-(-1z)=0

We get rid of parentheses

(7(-1z+4))/6+1z=0

We multiply all the terms by the denominator


(7(-1z+4))+1z*6=0



We calculate terms in parentheses: +(7(-1z+4)), so:

7(-1z+4)

We multiply parentheses

-7z+28

Back to the equation:

+(-7z+28)



Wy multiply elements

(-7z+28)+6z=0

We get rid of parentheses

-7z+6z+28=0

We add all the numbers together, and all the variables

-1z+28=0

We move all terms containing z to the left, all other terms to the right

-z=-28

z=-28/-1

z=+28

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