6(x-2)-3(x-1)=4x+3(x-2)

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Solution for 6(x-2)-3(x-1)=4x+3(x-2) equation: 



6(x-2)-3(x-1)=4x+3(x-2)

We move all terms to the left:

6(x-2)-3(x-1)-(4x+3(x-2))=0

We multiply parentheses

6x-3x-(4x+3(x-2))-12+3=0



We calculate terms in parentheses: -(4x+3(x-2)), so:

4x+3(x-2)

We multiply parentheses

4x+3x-6

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

3x-(7x-6)-9=0

We get rid of parentheses

3x-7x+6-9=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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