6(x-2)+12(3-x)=6

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Solution for 6(x-2)+12(3-x)=6 equation: 



6(x-2)+12(3-x)=6

We move all terms to the left:

6(x-2)+12(3-x)-(6)=0

We add all the numbers together, and all the variables

6(x-2)+12(-1x+3)-6=0

We multiply parentheses

6x-12x-12+36-6=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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