X2-200x+9600=0

Solution for X2-200x+9600=0 equation:

X2-200X+9600=0

We add all the numbers together, and all the variables

X^2-200X+9600=0

a = 1; b = -200; c = +9600;
Δ = b2-4ac
Δ = -2002-4·1·9600
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-40}{2*1}=\frac{160}{2}
=80
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+40}{2*1}=\frac{240}{2}
=120
$