6(x-1)/9=2(x+3)/7

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Solution for 6(x-1)/9=2(x+3)/7 equation: 



6(x-1)/9=2(x+3)/7

We move all terms to the left:

6(x-1)/9-(2(x+3)/7)=0

We calculate fractions


6x/()+(-(2(x+3)*9)/()=0



We calculate terms in parentheses: +(-(2(x+3)*9)/(), so:

-(2(x+3)*9)/(

We multiply all the terms by the denominator


-(2(x+3)*9)



We calculate terms in parentheses: -(2(x+3)*9), so:

2(x+3)*9

We multiply parentheses

18x+54

Back to the equation:

-(18x+54)



We get rid of parentheses

-18x-54

Back to the equation:

+(-18x-54)



We get rid of parentheses

6x/()-18x-54=0

We multiply all the terms by the denominator


6x-18x*()-54*()=0

We add all the numbers together, and all the variables

6x-18x*()=0

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