4(3x-3)=7(5-x)+10

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Solution for 4(3x-3)=7(5-x)+10 equation:



4(3x-3)=7(5-x)+10
We move all terms to the left:
4(3x-3)-(7(5-x)+10)=0
We add all the numbers together, and all the variables
4(3x-3)-(7(-1x+5)+10)=0
We multiply parentheses
12x-(7(-1x+5)+10)-12=0
We calculate terms in parentheses: -(7(-1x+5)+10), so:
7(-1x+5)+10
We multiply parentheses
-7x+35+10
We add all the numbers together, and all the variables
-7x+45
Back to the equation:
-(-7x+45)
We get rid of parentheses
12x+7x-45-12=0
We add all the numbers together, and all the variables
19x-57=0
We move all terms containing x to the left, all other terms to the right
19x=57
x=57/19
x=3

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