350=x+(x+20)+((x+20)-32)

Solution for 350=x+(x+20)+((x+20)-32) equation:

350=x+(x+20)+((x+20)-32)

We move all terms to the left:

350-(x+(x+20)+((x+20)-32))=0


We calculate terms in parentheses: -(x+(x+20)+((x+20)-32)), so:

x+(x+20)+((x+20)-32)

We get rid of parentheses

x+x+((x+20)-32)+20


We calculate terms in parentheses: +((x+20)-32), so:

(x+20)-32

We get rid of parentheses

x+20-32

We add all the numbers together, and all the variables

x-12

Back to the equation:

+(x-12)


We add all the numbers together, and all the variables

2x+(x-12)+20

We get rid of parentheses

2x+x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)


We get rid of parentheses

-3x-8+350=0

We add all the numbers together, and all the variables

-3x+342=0

We move all terms containing x to the left, all other terms to the right

-3x=-342

x=-342/-3

x=+114