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6(x-1)+1=3(x+1)-7
We move all terms to the left:
6(x-1)+1-(3(x+1)-7)=0
We multiply parentheses
6x-(3(x+1)-7)-6+1=0
We calculate terms in parentheses: -(3(x+1)-7), so:We add all the numbers together, and all the variables
3(x+1)-7
We multiply parentheses
3x+3-7
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
6x-(3x-4)-5=0
We get rid of parentheses
6x-3x+4-5=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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