4(2y-1)=-10(y-2)

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Solution for 4(2y-1)=-10(y-2) equation: 



4(2y-1)=-10(y-2)

We move all terms to the left:

4(2y-1)-(-10(y-2))=0

We multiply parentheses

8y-(-10(y-2))-4=0



We calculate terms in parentheses: -(-10(y-2)), so:

-10(y-2)

We multiply parentheses

-10y+20

Back to the equation:

-(-10y+20)



We get rid of parentheses

8y+10y-20-4=0

We add all the numbers together, and all the variables

18y-24=0

We move all terms containing y to the left, all other terms to the right

18y=24

y=24/18

y=1+1/3

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