6(x-1)+12=3(3x+2)

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Solution for 6(x-1)+12=3(3x+2) equation: 



6(x-1)+12=3(3x+2)

We move all terms to the left:

6(x-1)+12-(3(3x+2))=0

We multiply parentheses

6x-(3(3x+2))-6+12=0



We calculate terms in parentheses: -(3(3x+2)), so:

3(3x+2)

We multiply parentheses

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

6x-(9x+6)+6=0

We get rid of parentheses

6x-9x-6+6=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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