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4x(7x-9)=90
We move all terms to the left:
4x(7x-9)-(90)=0
We multiply parentheses
28x^2-36x-90=0
a = 28; b = -36; c = -90;
Δ = b2-4ac
Δ = -362-4·28·(-90)
Δ = 11376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11376}=\sqrt{144*79}=\sqrt{144}*\sqrt{79}=12\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{79}}{2*28}=\frac{36-12\sqrt{79}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{79}}{2*28}=\frac{36+12\sqrt{79}}{56} $
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