10(2x-3)-8(3x+10)=6x+30

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Solution for 10(2x-3)-8(3x+10)=6x+30 equation: 



10(2x-3)-8(3x+10)=6x+30

We move all terms to the left:

10(2x-3)-8(3x+10)-(6x+30)=0

We multiply parentheses

20x-24x-(6x+30)-30-80=0

We get rid of parentheses

20x-24x-6x-30-30-80=0

We add all the numbers together, and all the variables

-10x-140=0

We move all terms containing x to the left, all other terms to the right

-10x=140

x=140/-10

x=-14

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