6(x+3)=9x+27

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Solution for 6(x+3)=9x+27 equation: 



6(x+3)=9x+27

We move all terms to the left:

6(x+3)-(9x+27)=0

We multiply parentheses

6x-(9x+27)+18=0

We get rid of parentheses

6x-9x-27+18=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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