5-(3y-2)=4y-(y+7)

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Solution for 5-(3y-2)=4y-(y+7) equation: 



5-(3y-2)=4y-(y+7)

We move all terms to the left:

5-(3y-2)-(4y-(y+7))=0

We get rid of parentheses

-3y-(4y-(y+7))+2+5=0



We calculate terms in parentheses: -(4y-(y+7)), so:

4y-(y+7)

We get rid of parentheses

4y-y-7

We add all the numbers together, and all the variables

3y-7

Back to the equation:

-(3y-7)



We add all the numbers together, and all the variables

-3y-(3y-7)+7=0

We get rid of parentheses

-3y-3y+7+7=0

We add all the numbers together, and all the variables

-6y+14=0

We move all terms containing y to the left, all other terms to the right

-6y=-14

y=-14/-6

y=2+1/3

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