6(x+3)-x=-(x-4)+8

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Solution for 6(x+3)-x=-(x-4)+8 equation: 



6(x+3)-x=-(x-4)+8

We move all terms to the left:

6(x+3)-x-(-(x-4)+8)=0

We add all the numbers together, and all the variables

-1x+6(x+3)-(-(x-4)+8)=0

We multiply parentheses

-1x+6x-(-(x-4)+8)+18=0



We calculate terms in parentheses: -(-(x-4)+8), so:

-(x-4)+8

We get rid of parentheses

-x+4+8

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

5x-(-1x+12)+18=0

We get rid of parentheses

5x+1x-12+18=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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