6(x+3)+3x+2(2x+5)=3(x+1)-1

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Solution for 6(x+3)+3x+2(2x+5)=3(x+1)-1 equation: 



6(x+3)+3x+2(2x+5)=3(x+1)-1

We move all terms to the left:

6(x+3)+3x+2(2x+5)-(3(x+1)-1)=0

We add all the numbers together, and all the variables

3x+6(x+3)+2(2x+5)-(3(x+1)-1)=0

We multiply parentheses

3x+6x+4x-(3(x+1)-1)+18+10=0



We calculate terms in parentheses: -(3(x+1)-1), so:

3(x+1)-1

We multiply parentheses

3x+3-1

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

13x-(3x+2)+28=0

We get rid of parentheses

13x-3x-2+28=0

We add all the numbers together, and all the variables

10x+26=0

We move all terms containing x to the left, all other terms to the right

10x=-26

x=-26/10

x=-2+3/5

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