(3x+2)-(2x-7)(3x+2)=(3x+2)(-6-2x)

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Solution for (3x+2)-(2x-7)(3x+2)=(3x+2)(-6-2x) equation: 



(3x+2)-(2x-7)(3x+2)=(3x+2)(-6-2x)

We move all terms to the left:

(3x+2)-(2x-7)(3x+2)-((3x+2)(-6-2x))=0

We add all the numbers together, and all the variables

(3x+2)-(2x-7)(3x+2)-((3x+2)(-2x-6))=0

We get rid of parentheses

3x-(2x-7)(3x+2)-((3x+2)(-2x-6))+2=0

We multiply parentheses ..

-(+6x^2+4x-21x-14)+3x-((3x+2)(-2x-6))+2=0



We calculate terms in parentheses: -((3x+2)(-2x-6)), so:

(3x+2)(-2x-6)

We multiply parentheses ..

(-6x^2-18x-4x-12)

We get rid of parentheses

-6x^2-18x-4x-12

We add all the numbers together, and all the variables

-6x^2-22x-12

Back to the equation:

-(-6x^2-22x-12)



We get rid of parentheses

-6x^2+6x^2-4x+21x+22x+3x+14+12+2=0

We add all the numbers together, and all the variables

42x+28=0

We move all terms containing x to the left, all other terms to the right

42x=-28

x=-28/42

x=-2/3

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