6(x+3)+2(2x+2)=3(x+2)+4(x+6)

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Solution for 6(x+3)+2(2x+2)=3(x+2)+4(x+6) equation: 



6(x+3)+2(2x+2)=3(x+2)+4(x+6)

We move all terms to the left:

6(x+3)+2(2x+2)-(3(x+2)+4(x+6))=0

We multiply parentheses

6x+4x-(3(x+2)+4(x+6))+18+4=0



We calculate terms in parentheses: -(3(x+2)+4(x+6)), so:

3(x+2)+4(x+6)

We multiply parentheses

3x+4x+6+24

We add all the numbers together, and all the variables

7x+30

Back to the equation:

-(7x+30)



We add all the numbers together, and all the variables

10x-(7x+30)+22=0

We get rid of parentheses

10x-7x-30+22=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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