1-8(2x-5)=3x+11

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Solution for 1-8(2x-5)=3x+11 equation: 



1-8(2x-5)=3x+11

We move all terms to the left:

1-8(2x-5)-(3x+11)=0

We multiply parentheses

-16x-(3x+11)+40+1=0

We get rid of parentheses

-16x-3x-11+40+1=0

We add all the numbers together, and all the variables

-19x+30=0

We move all terms containing x to the left, all other terms to the right

-19x=-30

x=-30/-19

x=1+11/19

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