6(x+2)=4(x-4)+4x

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Solution for 6(x+2)=4(x-4)+4x equation: 



6(x+2)=4(x-4)+4x

We move all terms to the left:

6(x+2)-(4(x-4)+4x)=0

We multiply parentheses

6x-(4(x-4)+4x)+12=0



We calculate terms in parentheses: -(4(x-4)+4x), so:

4(x-4)+4x

We add all the numbers together, and all the variables

4x+4(x-4)

We multiply parentheses

4x+4x-16

We add all the numbers together, and all the variables

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

6x-8x+16+12=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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