4(3r+5)=5(4r-5)+7r

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Solution for 4(3r+5)=5(4r-5)+7r equation: 



4(3r+5)=5(4r-5)+7r

We move all terms to the left:

4(3r+5)-(5(4r-5)+7r)=0

We multiply parentheses

12r-(5(4r-5)+7r)+20=0



We calculate terms in parentheses: -(5(4r-5)+7r), so:

5(4r-5)+7r

We add all the numbers together, and all the variables

7r+5(4r-5)

We multiply parentheses

7r+20r-25

We add all the numbers together, and all the variables

27r-25

Back to the equation:

-(27r-25)



We get rid of parentheses

12r-27r+25+20=0

We add all the numbers together, and all the variables

-15r+45=0

We move all terms containing r to the left, all other terms to the right

-15r=-45

r=-45/-15

r=+3

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