6(n-4)+1=2n-35

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Solution for 6(n-4)+1=2n-35 equation: 



6(n-4)+1=2n-35

We move all terms to the left:

6(n-4)+1-(2n-35)=0

We multiply parentheses

6n-(2n-35)-24+1=0

We get rid of parentheses

6n-2n+35-24+1=0

We add all the numbers together, and all the variables

4n+12=0

We move all terms containing n to the left, all other terms to the right

4n=-12

n=-12/4

n=-3

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