6(x+2)=4(x-1)

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Solution for 6(x+2)=4(x-1) equation: 



6(x+2)=4(x-1)

We move all terms to the left:

6(x+2)-(4(x-1))=0

We multiply parentheses

6x-(4(x-1))+12=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

6x-4x+4+12=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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