6(x+2)=4(x+3)

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Solution for 6(x+2)=4(x+3) equation: 



6(x+2)=4(x+3)

We move all terms to the left:

6(x+2)-(4(x+3))=0

We multiply parentheses

6x-(4(x+3))+12=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

6x-4x-12+12=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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