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10((134-10y)/9)+9y=132
We move all terms to the left:
10((134-10y)/9)+9y-(132)=0
We add all the numbers together, and all the variables
10((-10y+134)/9)+9y-132=0
We add all the numbers together, and all the variables
9y+10((-10y+134)/9)-132=0
We multiply all the terms by the denominator
9y*9)+10((-10y+134)-132*9)=0
We add all the numbers together, and all the variables
9y*9)+10((-10y+134)=0
Wy multiply elements
81y^2=0
a = 81; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·81·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{162}=0$
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