6(x+2)=3(x+3)+6x-4

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Solution for 6(x+2)=3(x+3)+6x-4 equation: 



6(x+2)=3(x+3)+6x-4

We move all terms to the left:

6(x+2)-(3(x+3)+6x-4)=0

We multiply parentheses

6x-(3(x+3)+6x-4)+12=0



We calculate terms in parentheses: -(3(x+3)+6x-4), so:

3(x+3)+6x-4

We add all the numbers together, and all the variables

6x+3(x+3)-4

We multiply parentheses

6x+3x+9-4

We add all the numbers together, and all the variables

9x+5

Back to the equation:

-(9x+5)



We get rid of parentheses

6x-9x-5+12=0

We add all the numbers together, and all the variables

-3x+7=0

We move all terms containing x to the left, all other terms to the right

-3x=-7

x=-7/-3

x=2+1/3

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