6(x+2)=17-4x

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Solution for 6(x+2)=17-4x equation: 



6(x+2)=17-4x

We move all terms to the left:

6(x+2)-(17-4x)=0

We add all the numbers together, and all the variables

6(x+2)-(-4x+17)=0

We multiply parentheses

6x-(-4x+17)+12=0

We get rid of parentheses

6x+4x-17+12=0

We add all the numbers together, and all the variables

10x-5=0

We move all terms containing x to the left, all other terms to the right

10x=5

x=5/10

x=1/2

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