1/6(x+4)-4/9(x-3)=1/18

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Solution for 1/6(x+4)-4/9(x-3)=1/18 equation: 



1/6(x+4)-4/9(x-3)=1/18

We move all terms to the left:

1/6(x+4)-4/9(x-3)-(1/18)=0



Domain of the equation: 6(x+4)!=0

x∈R





Domain of the equation: 9(x-3)!=0

x∈R



We add all the numbers together, and all the variables

1/6(x+4)-4/9(x-3)-(+1/18)=0

We get rid of parentheses

1/6(x+4)-4/9(x-3)-1/18=0

We calculate fractions


(162xx/(6(x+4)*9(x-3)*18)+(-432xx/(6(x+4)*9(x-3)*18)+(-54x^2x/(6(x+4)*9(x-3)*18)=0



We calculate terms in parentheses: +(162xx/(6(x+4)*9(x-3)*18)+(-432xx/(6(x+4)*9(x-3)*18)+(-54x^2x/(6(x+4)*9(x-3)*18), so:

162xx/(6(x+4)*9(x-3)*18)+(-432xx/(6(x+4)*9(x-3)*18)+(-54x^2x/(6(x+4)*9(x-3)*18

We can not solve this equation

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