6(x+2)=1-2(x+3)

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Solution for 6(x+2)=1-2(x+3) equation: 



6(x+2)=1-2(x+3)

We move all terms to the left:

6(x+2)-(1-2(x+3))=0

We multiply parentheses

6x-(1-2(x+3))+12=0



We calculate terms in parentheses: -(1-2(x+3)), so:

1-2(x+3)

determiningTheFunctionDomain
-2(x+3)+1

We multiply parentheses

-2x-6+1

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We get rid of parentheses

6x+2x+5+12=0

We add all the numbers together, and all the variables

8x+17=0

We move all terms containing x to the left, all other terms to the right

8x=-17

x=-17/8

x=-2+1/8

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