20(-4x+3)=12(x-3)

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Solution for 20(-4x+3)=12(x-3) equation: 



20(-4x+3)=12(x-3)

We move all terms to the left:

20(-4x+3)-(12(x-3))=0

We multiply parentheses

-80x-(12(x-3))+60=0



We calculate terms in parentheses: -(12(x-3)), so:

12(x-3)

We multiply parentheses

12x-36

Back to the equation:

-(12x-36)



We get rid of parentheses

-80x-12x+36+60=0

We add all the numbers together, and all the variables

-92x+96=0

We move all terms containing x to the left, all other terms to the right

-92x=-96

x=-96/-92

x=1+1/23

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