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6(x+2)-2=3x+3(4+x)
We move all terms to the left:
6(x+2)-2-(3x+3(4+x))=0
We add all the numbers together, and all the variables
6(x+2)-(3x+3(x+4))-2=0
We multiply parentheses
6x-(3x+3(x+4))+12-2=0
We calculate terms in parentheses: -(3x+3(x+4)), so:We add all the numbers together, and all the variables
3x+3(x+4)
We multiply parentheses
3x+3x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
6x-(6x+12)+10=0
We get rid of parentheses
6x-6x-12+10=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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