6(x+2)+2x-4=8(x-2)+8x=

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Solution for 6(x+2)+2x-4=8(x-2)+8x= equation: 



6(x+2)+2x-4=8(x-2)+8x=

We move all terms to the left:

6(x+2)+2x-4-(8(x-2)+8x)=0

We add all the numbers together, and all the variables

2x+6(x+2)-(8(x-2)+8x)-4=0

We multiply parentheses

2x+6x-(8(x-2)+8x)+12-4=0



We calculate terms in parentheses: -(8(x-2)+8x), so:

8(x-2)+8x

We add all the numbers together, and all the variables

8x+8(x-2)

We multiply parentheses

8x+8x-16

We add all the numbers together, and all the variables

16x-16

Back to the equation:

-(16x-16)



We add all the numbers together, and all the variables

8x-(16x-16)+8=0

We get rid of parentheses

8x-16x+16+8=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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