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12+7x-21=3(x-3)+4x
We move all terms to the left:
12+7x-21-(3(x-3)+4x)=0
We add all the numbers together, and all the variables
7x-(3(x-3)+4x)-9=0
We calculate terms in parentheses: -(3(x-3)+4x), so:We get rid of parentheses
3(x-3)+4x
We add all the numbers together, and all the variables
4x+3(x-3)
We multiply parentheses
4x+3x-9
We add all the numbers together, and all the variables
7x-9
Back to the equation:
-(7x-9)
7x-7x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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