6(x+2)+2(x-2)=40

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Solution for 6(x+2)+2(x-2)=40 equation: 



6(x+2)+2(x-2)=40

We move all terms to the left:

6(x+2)+2(x-2)-(40)=0

We multiply parentheses

6x+2x+12-4-40=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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