0=-2t(8t-9)

Solution for 0=-2t(8t-9) equation:

0=-2t(8t-9)

We move all terms to the left:

0-(-2t(8t-9))=0

We add all the numbers together, and all the variables

-(-2t(8t-9))=0


We calculate terms in parentheses: -(-2t(8t-9)), so:

-2t(8t-9)

We multiply parentheses

-16t^2+18t

Back to the equation:

-(-16t^2+18t)


We get rid of parentheses

16t^2-18t=0

a = 16; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·16·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*16}=\frac{36}{32}
=1+1/8
$