6(x+2)+(4x-3)=50

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Solution for 6(x+2)+(4x-3)=50 equation: 



6(x+2)+(4x-3)=50

We move all terms to the left:

6(x+2)+(4x-3)-(50)=0

We multiply parentheses

6x+(4x-3)+12-50=0

We get rid of parentheses

6x+4x-3+12-50=0

We add all the numbers together, and all the variables

10x-41=0

We move all terms containing x to the left, all other terms to the right

10x=41

x=41/10

x=4+1/10

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