7(2c+1)-(2c-5)=0

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Solution for 7(2c+1)-(2c-5)=0 equation: 



7(2c+1)-(2c-5)=0

We multiply parentheses

14c-(2c-5)+7=0

We get rid of parentheses

14c-2c+5+7=0

We add all the numbers together, and all the variables

12c+12=0

We move all terms containing c to the left, all other terms to the right

12c=-12

c=-12/12

c=-1

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